Source code for cvxpy.reductions.chain
from cvxpy import settings as s
from cvxpy.reductions.reduction import Reduction
[docs]
class Chain(Reduction):
"""A logical grouping of multiple reductions into a single reduction.
Attributes
----------
reductions : list[Reduction]
A list of reductions.
"""
def __init__(self, problem=None, reductions=None) -> None:
super(Chain, self).__init__(problem=problem)
self.reductions = [] if reductions is None else reductions
def __str__(self):
return str(self.reductions)
def __repr__(self) -> str:
return "Chain(reductions=%s)" % repr(self.reductions)
def get(self, reduction_type):
for reduction in self.reductions:
if isinstance(reduction, reduction_type):
return reduction
raise KeyError
[docs]
def accepts(self, problem) -> bool:
"""A problem is accepted if the sequence of reductions is valid.
In particular, the i-th reduction must accept the output of the i-1th
reduction, with the first reduction (self.reductions[0])
in the sequence taking as input the supplied problem.
Parameters
----------
problem : Problem
The problem to check.
Returns
-------
bool
True if the chain can be applied, False otherwise.
"""
for r in self.reductions:
if not r.accepts(problem):
return False
problem, _ = r.apply(problem)
return True
[docs]
def apply(self, problem, verbose: bool = False):
"""Applies the chain to a problem and returns an equivalent problem.
Parameters
----------
problem : Problem
The problem to which the chain will be applied.
verbose : bool, optional
Whehter to print verbose output.
Returns
-------
Problem or dict
The problem yielded by applying the reductions in sequence,
starting at self.reductions[0].
list
The inverse data yielded by each of the reductions.
"""
inverse_data = []
for r in self.reductions:
if verbose:
s.LOGGER.info('Applying reduction %s', type(r).__name__)
problem, inv = r.apply(problem)
inverse_data.append(inv)
return problem, inverse_data
[docs]
def invert(self, solution, inverse_data):
"""Returns a solution to the original problem given the inverse_data.
"""
for r, inv in reversed(list(zip(self.reductions, inverse_data))):
solution = r.invert(solution, inv)
return solution